A number
eval-two-digits-plus

Make eval handle "3+5": character 0 is the left digit, character 1 is the +, character 2 is the right digit. Add them.

    check("3+5", 8);
fn eval(input: []const u8) i64 {
    const a: i64 = @as(i64, input[0] - '0');
    const b: i64 = @as(i64, input[2] - '0');
    return a + b;
}

We're ignoring the operator. Hardcoded addition. Let's fix that.